areas of parallelograms and triangles class 9 ncert solutions, areas of parallelograms and triangles, areas of parallelograms and triangles class 9 , ncert solutions, chapter 9,chapter 9ncert solutions, areas of parallelograms and triangles ncert solutions, ncert solutions for class 9 maths, class 9 maths ncert solutions, ncert solutions for class 9, ncert class 9 maths, class 9 maths, class 9 maths solution, ncert solutions class 9, class 9 maths , ncert class 9, class 9 maths chapter 9,chapter 9 areas of parallelograms and triangles ncert solutions

**Question1.** Which of the following figures lie on the same base and between the same parallels.
In such a case, write the common base and the two parallels.

EXERCISE 9.2

**Question 1.** In Fig. 9.15, ABCD is a parallelogram, AE ⊥ DC
and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and
CF = 10 cm, find AD.

**Question 2.** If E,F,G and H are respectively the mid-points of
the sides of a parallelogram ABCD, show that
ar (EFGH) =
1 ar (ABCD)
2
.

**Question 3.** P and Q are any two points lying on the sides DC and AD respectively of a parallelogram
ABCD. Show that ar (APB) = ar (BQC).

**Question 4.** In Fig. 9.16, P is a point in the interior of a
parallelogram ABCD. Show that:

(i) ar (APB) + ar (PCD) =
1 ar (ABCD)
2

(ii) ar (APD) + ar (PBC) = ar (APB) + ar (PCD)
[Hint : Through P, draw a line parallel to AB.]

**Question 5.** . In Fig. 9.17, PQRS and ABRS are parallelograms
and X is any point on side BR. Show that

(i) ar (PQRS) = ar (ABRS)

(ii) ar (AX S) =
1 ar (PQRS)

**Question 6.** A farmer was having a field in the form of a parallelogram PQRS. She took any point A
on RS and joined it to points P and Q. In how many parts the fields is divided? What
are the shapes of these parts? The farmer wants to sow wheat and pulses in equal
portions of the field separately. How should she do it?

**Question 1.** In Fig.9.23, E is any point on median AD of a
Δ ABC. Show that ar (ABE) = ar (ACE).

**Question 2.** In a triangle ABC, E is the mid-point of median
AD. Show that ar (BED) =
1 ar(ABC)
4
.

**Question 2.** Show that the diagonals of a parallelogram divide
it into four triangles of equal area.

**Question 4.** In Fig. 9.24, ABC and ABD are two triangles on
the same base AB. If line- segment CD is bisected
by AB at O, show that ar(ABC) = ar (ABD).

**Question 5.** D, E and F are respectively the mid-points of the sides BC, CA and AB of a Δ ABC.
Show that

(i) BDEF is a parallelogram.

(ii) ar (DEF) =
1
4
ar (ABC)

(iii) ar (BDEF) =
1
2
ar (ABC)

**Question 6.** In Fig. 9.25, diagonals AC and BD of quadrilateral
ABCD intersect at O such that OB = OD.
If AB = CD, then show that:

(i) ar (DOC) = ar (AOB)

(ii) ar (DCB) = ar (ACB)

(iii) DA || CB or ABCD is a parallelogram.
[Hint : From D and B, draw perpendiculars to AC.]

**Question 7.** D and E are points on sides AB and AC respectively of Δ ABC such that
ar (DBC) = ar (EBC). Prove that DE || BC.

**Question 8.** XY is a line parallel to side BC of a triangle ABC. If BE || AC and CF || AB meet XY at E
and F respectively, show that
ar (ABE) = ar (ACF)

**Question 9.** The side AB of a parallelogram ABCD is produced
to any point P. A line through A and parallel to CP
meets CB produced at Q and then parallelogram
PBQR is completed (see Fig. 9.26). Show that
ar (ABCD) = ar (PBQR).
[Hint : Join AC and PQ. Now compare ar (ACQ)
and ar (APQ).]

**Question 10.** Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O.
Prove that ar (AOD) = ar (BOC).

**Question 11.** In Fig. 9.27, ABCDE is a pentagon. A line through
B parallel to AC meets DC produced at F. Show
that

(i) ar (ACB) = ar (ACF)

(ii) ar (AEDF) = ar (ABCDE)

**Question 12.** A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat
of the village decided to take over some portion of his plot from one of the corners to
construct a Health Centre. Itwaari agrees to the above proposal with the condition
that he should be given equal amount of land in lieu of his land adjoining his plot so
as to form a triangular plot. Explain how this proposal will be implemented.

**Question 13.** ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC
at Y. Prove that ar (ADX) = ar (ACY).
[Hint : Join CX.]

**Question 14.** In Fig.9.28, AP || BQ || CR. Prove that
ar (AQC) = ar (PBR).

**Question 15.** . Diagonals AC and BD of a quadrilateral
ABCD intersect at O in such a way that
ar (AOD) = ar (BOC). Prove that ABCD is a
trapezium.

**Question 16.** In Fig.9.29, ar (DRC) = ar (DPC) and
ar (BDP) = ar (ARC). Show that both the
quadrilaterals ABCD and DCPR are
trapeziums.

**Question 1.** Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal
areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

**Question 2.** In Fig. 9.30, D and E are two points on BC
such that BD = DE = EC. Show that
ar (ABD) = ar (ADE) = ar (AEC).
Can you now answer the question that you have
left in the ‘Introduction’ of this chapter, whether
the field of Budhia has been actually divided
into three parts of equal area? triangles ABD, ADE and AEC of equal areas. In the same way, by dividing BC into n
equal parts and joining the points of division so obtained to the opposite vertex of
BC, you can divide ΔABC into n triangles of equal areas.]

**Question 3.** In Fig. 9.31, ABCD, DCFE and ABFE are parallelograms. Show that
ar (ADE) = ar (BCF).

**Question 4.** In Fig. 9.32, ABCD is a parallelogram and BC is produced to a point Q such that
AD = CQ. If AQ intersect DC at P, show that ar (BPC) = ar (DPQ).
[Hint : Join AC.]

**Question 5.** In Fig.9.33, ABC and BDE are two equilateral
triangles such that D is the mid-point of BC. If AE
intersects BC at F, show that:

(i) ar (BDE) =
1
4
ar (ABC)

(ii) ar (BDE) =
1
2
ar (BAE)

(iii) ar (ABC) = 2 ar (BEC)

(iv) ar (BFE) = ar (AFD)

(v) ar (BFE) = 2 ar (FED)

(vi) ar (FED) =
1
8 ar (AFC)
[Hint : Join EC and AD. Show that BE || AC and DE || AB, etc.]

**Question 6.** Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that
ar (APB) × ar (CPD) = ar (APD) × ar (BPC).
[Hint : From A and C, draw perpendiculars to BD.]

**Question 7.** P and Q are respectively the mid-points of sides AB and BC of a triangle ABC and R
is the mid-point of AP, show that
:

(i) ar (PRQ) =
1
2
ar (ARC)

(ii) ar (RQC) =
3
8 ar (ABC)

(iii) ar (PBQ) = ar (ARC)

**Question 8.** In Fig. 9.34, ABC is a right triangle right angled at A. BCED, ACFG and ABMN are
squares on the sides BC, CA and AB respectively. Line segment AX ⊥ DE meets BC
at Y. Show that:

(i) Δ MBC Δ ABD

(ii) ar (BYXD) = 2 ar (MBC)

(iii) ar (BYXD) = ar (ABMN)

(iv) Δ FCB Δ ACE

(v) ar (CYXE) = 2 ar (FCB)

(vi) ar (CYXE) = ar (ACFG)

(vii) ar (BCED) = ar (ABMN) + ar (ACFG)
Note : Result

(vii) is the famous Theorem of Pythagoras. You shall learn a simpler
proof of this theorem in Class X.

Please Wait pdf file is loading **(कृपया इंतजार करें pdf file लोड हो रही है)...**

Loading speed will depend up on your download speed. **Pdf file के लोड होने में लगा समय आपकी डाउनलोड स्पीड पर निर्भर करेगा **

Loading document ...

Loading page ...

To download above pdf file Link is **given below**.

उपर दिखायी दे रही पीडीऍफ़ को डाउनलोड करने का लिंक**नीचे दिया गया है **

उपर दिखायी दे रही पीडीऍफ़ को डाउनलोड करने का लिंक

- Chapter 1: Number System
**[Ques wise Ans]** - Chapter 2: Polynomial
**[Ques wise Ans]** - Chapter 5: INTRODUCTION TO EUCLID’S GEOMETRY
**[Ques wise Ans]** - Chapter 6: LINES AND ANGLES
**[Ques wise Ans]** - Chapter 3 Coordinate Geometry
- Chapter 4 Linear Equations in Two Variables
- Chapter 7 Triangles
- Chapter 8 Quadrilaterals
- Chapter 9 Areas of Parallelograms and Triangles
- Chapter 10 Circles
- Chapter 11 Constructions
- Chapter 12 Heron’s Formula
- Chapter 13 Surface Areas and Volumes
- Chapter 14 Statistics
- Chapter 15 Probability

- NCERT Solutions for Class 9
- NCERT Solutions for Class 10
- NCERT Solutions for Class 11
- NCERT Solutions for Class 12

If You have any problem/query related to above page please send us your Query to [email protected] with code **Serial No1455/1101**. Thanks

Copyright @ ncerthelp.com A free educational website for CBSE, ICSE and UP board.